C\u00e1ch nu\u00f4i l\u00f4 k\u00e9p theo khung<\/strong><\/h2>\n\n\n\nNu\u00f4i l\u00f4 k\u00e9p<\/strong> theo khung c\u00f3 r\u1ea5t nhi\u1ec1u c\u00e1ch kh\u00e1c nhau, d\u01b0\u1edbi \u0111\u00e2y l\u00e0 m\u1ed9t s\u1ed1 th\u00f4ng tin b\u1ea1n c\u00f3 th\u1ec3 tham kh\u1ea3o: <\/p>\n\n\n\nNu\u00f4i l\u00f4 k\u00e9p khung 3 ng\u00e0y <\/em><\/strong><\/h3>\n\n\n\nL\u00f4 k\u00e9p khung 3 ng\u00e0y l\u00e0 g\u00ec?<\/em><\/h4>\n\n\n\nL\u00f4 k\u00e9p khung 3 ng\u00e0y <\/strong>l\u00e0 ph\u01b0\u01a1ng ph\u00e1p \u0111\u01b0\u1ee3c \u0111a s\u1ed1 ng\u01b0\u1eddi ch\u01a1i c\u00f3 s\u1ed1 v\u1ed1n d\u01b0\u1edbi 1 tri\u1ec7u. \u0110\u1eb7c bi\u1ec7t l\u00e0 ph\u00f9 h\u1ee3p v\u1edbi nh\u1eefng ng\u01b0\u1eddi kh\u00f4ng c\u00f3 gan \u0111\u00e1nh l\u1edbn. V\u00ec v\u1eady khi tham gia theo ph\u01b0\u01a1ng ph\u00e1p n\u00e0y b\u1ea1n c\u00f3 th\u1ec3 g\u1ea5p ti\u1ec1n theo t\u1ef7 l\u1ec7 \u2153. B\u1ea1n c\u00f3 th\u1ec3 hi\u1ec3u h\u01a1n v\u1ec1 l\u00f4 khung 3 ng\u00e0y qua v\u00ed d\u1ee5 sau \u0111\u00e2y:<\/p>\n\n\n\nNg\u00e0y \u0111\u1ea7u ti\u00ean b\u1ea1n ch\u01a1i 5 \u0111i\u1ec3m cho 1 con. Nh\u01b0ng ng\u00e0y \u0111\u00f3 c\u1eb7p s\u1ed1 \u0111\u00f3 v\u1eabn ch\u01b0a v\u1ec1 th\u00ec sang ng\u00e0y th\u1ee9 2 b\u1ea1n c\u00f3 th\u1ec3 ch\u01a1i th\u00eam 15 \u0111i\u1ec3m cho 1 con. \u0110\u1ebfn ng\u00e0y th\u1ee9 3 ti\u1ebfp t\u1ee5c n\u00e2ng l\u00ean l\u00e0 20 \u0111i\u1ec3m cho 1 con. N\u1ebfu h\u1ebft khung trong 3 ng\u00e0y m\u00e0 con l\u00f4 \u0111\u00f3 v\u1eabn kh\u00f4ng ra th\u00ec b\u1ea1n n\u00ean \u0111\u1ed5i th\u00e0nh m\u1ed9t khung m\u1edbi. Tuy nhi\u00ean ph\u1ea3i b\u1eaft \u0111\u1ea7u ch\u01a1i \u1edf m\u1ee9c ng\u00e0y 1 l\u00e0 5 \u0111i\u1ec3m\/1 con. <\/p>\n\n\n\n
C\u00e1ch nu\u00f4i l\u00f4 khung k\u00e9p 3 ng\u00e0y<\/em><\/h4>\n\n\n\n\u0110\u1ec3 ch\u01a1i l\u00f4 \u0111\u1ec1 theo ph\u01b0\u01a1ng ph\u00e1p l\u00f4 khung 3 ng\u00e0y b\u1ea1n c\u1ea7n d\u1ef1a v\u00e0o b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 theo ph\u01b0\u01a1ng ph\u00e1p sau: <\/p>\n\n\n\n
- L\u1ea5y con th\u1ee9 1 v\u00e0 th\u1ee9 3 trong gi\u1ea3i 3.6 l\u00e0m c\u1ea7u nu\u00f4i trong 3 ng\u00e0y. V\u00ed d\u1ee5: Gi\u1ea3i 3.6 c\u1ee7a h\u00f4m nay v\u1ec1 l\u00e0 84693 th\u00ec h\u00f4m sau b\u1ea1n s\u1ebd nu\u00f4i l\u00f4 86. <\/li>
- B\u1eaft \u0111\u1ea7u ch\u01a1i t\u1eeb th\u1ee9 2 th\u00ec d\u1ef1a v\u00e0o b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 c\u1ee7a ng\u00e0y ch\u1ee7 nh\u1eadt. \u0110\u1eb7c bi\u1ec7t l\u00e0 ch\u00fa \u00fd \u1edf gi\u1ea3i 5 v\u00e0 gi\u1ea3i 6 \u0111\u1ec3 gh\u00e9p hai s\u1ed1 \u0111\u1ea7u ti\u00ean v\u1edbi nhau v\u00e0 nu\u00f4i trong v\u00f2ng 3 ng\u00e0y. <\/li>
- C\u1ed9ng 2 s\u1ed1 c\u1ee7a gi\u1ea3i 7.3 \u0111\u1ec3 s\u1eed d\u1ee5ng l\u00e0m l\u00f4 khung 3 ng\u00e0y. V\u00ed d\u1ee5: Gi\u1ea3i 7.3 c\u1ee7a ng\u00e0y h\u00f4m nay l\u00e0 73 th\u00ec b\u1ea1n d\u00f9ng 7+3=10, \u0111\u00e1nh l\u00f4 01. Ch\u1ecdn con th\u1ee9 2 c\u1ee7a gi\u1ea3i 4.3 v\u00e0 4.4 V\u00ed d\u1ee5 gi\u1ea3i 4.3 c\u00f3 k\u1ebft qu\u1ea3 l\u00e0 2253, v\u00e0 4.4 l\u00e0 2943 th\u00ec ng\u00e0y h\u00f4m sau b\u1ea1n n\u00ean nu\u00f4i khung 3 ng\u00e0y cho con 29. <\/li>
- C\u1ed9ng d\u1ed3n t\u1ea5t c\u1ea3 c\u00e1c s\u1ed1 c\u1ee7a gi\u1ea3i 7 l\u1ea1i v\u1edbi nhau \u0111\u1ec3 c\u00f3 con s\u1ed1 nu\u00f4i 2 ng\u00e0y. V\u00ed d\u1ee5: Gi\u1ea3i 7 c\u1ee7a ng\u00e0y h\u00f4m nay l\u00e0 51\u201392\u201370\u201390. B\u1ea1n c\u1ed9ng d\u1ed3n 51 + 92 + 70 + 90 = 203, v\u1eady \u0111\u00e1nh 03<\/li>
- Gh\u00e9p c\u1ea7u c\u1ee7a s\u1ed1 th\u1ee9 2 v\u00e0 th\u1ee9 3 trong gi\u1ea3i 5.2 v\u1edbi nhau. V\u00ed d\u1ee5 gi\u1ea3i 5.2 l\u00e0 2792 th\u00ec ng\u00e0y h\u00f4m sau b\u1ea1n nu\u00f4i l\u00f4 79. <\/li><\/ul>\n\n\n\n