D\u00f2 s\u1ed1 tr\u00fang Vietlott Max 3D plus<\/em><\/strong><\/h3>\n\n\n\nC\u00e1ch xem tr\u00fang th\u01b0\u1edfng Vietlott<\/strong> Max 3D plus kh\u00f4ng qu\u00e1 kh\u00f3 kh\u0103n. B\u1ea1n tham kh\u1ea3o th\u00f4ng tin sau \u0111\u00e2y: <\/p>\n\n\n\n- Gi\u1ea3i nh\u1ea5t: Tr\u00fang c\u1ea3 hai s\u1ed1 quay th\u01b0\u1edfng c\u1ee7a gi\u1ea3i nh\u1ea5t. Ti\u1ec1n th\u01b0\u1edfng nh\u1eadn \u0111\u01b0\u1ee3c l\u00e0 1.000.000.000 Vn\u0111<\/li>
- Gi\u1ea3i nh\u00ec: Tr\u00fang b\u1ea5t k\u1ef3 hai trong b\u1ed1n s\u1ed1 c\u1ee7a gi\u1ea3i nh\u00ec. Ti\u1ec1n th\u01b0\u1edfng nh\u1eadn \u0111\u01b0\u1ee3c l\u00e0 40.000.000 Vn\u0111<\/li>
- Gi\u1ea3i ba: Tr\u00fang b\u1ea5t k\u1ef3 hai trong s\u00e1u s\u1ed1 c\u1ee7a gi\u1ea3i ba. Ti\u1ec1n th\u01b0\u1edfng nh\u1eadn \u0111\u01b0\u1ee3c l\u00e0 10.000.000 Vn\u0111<\/li>
- Gi\u1ea3i t\u01b0: Tr\u00fang b\u1ea5t k\u1ef3 hai trong t\u00e1m s\u1ed1 c\u1ee7a gi\u1ea3i t\u01b0. Ti\u1ec1n th\u01b0\u1edfng nh\u1eadn \u0111\u01b0\u1ee3c l\u00e0 5.000.000 Vn\u0111<\/li>
- Gi\u1ea3i n\u0103m: Tr\u00fang b\u1ea5t k\u1ef3 hai s\u1ed1 quay thu\u1ed9c gi\u1ea3i nh\u1ea5t, ba, nh\u00ec ho\u1eb7c khuy\u1ebfn kh\u00edch. Ti\u1ec1n th\u01b0\u1edfng nh\u1eadn \u0111\u01b0\u1ee3c l\u00e0 1.000.000 Vn\u0111<\/li>
- Gi\u1ea3i s\u00e1u: Tr\u00fang m\u1ed9t s\u1ed1 quay th\u01b0\u1edfng b\u1ea5t k\u1ef3 c\u1ee7a gi\u1ea3i nh\u1ea5t Ti\u1ec1n th\u01b0\u1edfng nh\u1eadn \u0111\u01b0\u1ee3c l\u00e0 150.000 Vn\u0111<\/li>
- Gi\u1ea3i b\u1ea3y: Tr\u00fang m\u1ed9t s\u1ed1 quay th\u01b0\u1edfng b\u1ea5t k\u1ef3 c\u1ee7a gi\u1ea3i ba, nh\u00ec ho\u1eb7c khuy\u1ebfn kh\u00edch. Ti\u1ec1n th\u01b0\u1edfng nh\u1eadn \u0111\u01b0\u1ee3c l\u00e0 40.000 Vn\u0111<\/li><\/ul>\n\n\n\n
C\u00e1ch d\u00f2 s\u1ed1 Vietlott tr\u00fang gi\u1ea3i Keno<\/strong><\/h2>\n\n\n\nH\u00e0ng ng\u00e0y, \u0111i\u1ec7n to\u00e1n Keno s\u1ebd x\u1ed5 10 ph\u00fat\/ l\u1ea7n, li\u00ean t\u1ee5c trong 6h00 – 21h55. B\u1ea1n tham gia qua c\u00e1ch b\u1ecf ra 10.000 Vn\u0111\/ c\u1eb7p s\u1ed1. C\u00f3 t\u1ed5ng c\u1ed9ng 10 c\u1eb7p s\u1ed1 trong 1 l\u1ea7n ch\u01a1i t\u1eeb 1 – 80. T\u1eebng l\u1ea7n x\u1ed5 s\u1ebd l\u00e0 20 s\u1ed1, ng\u01b0\u1eddi ch\u01a1i so s\u00e1nh nh\u1eefng c\u1eb7p s\u1ed1 m\u00ecnh \u0111\u00e3 ch\u1ecdn xem c\u00f3 tr\u00fang hay kh\u00f4ng. <\/p>\n\n\n\n
C\u00e1ch d\u00f2 c\u0169ng kh\u00e1 \u0111\u01a1n gi\u1ea3n nh\u01b0 sau: <\/p>\n\n\n\n
- C\u1eb7p s\u1ed1 ch\u01a1i l\u00e0 1: Tr\u00fang 1 trong 20 con \u0111\u00e3 x\u1ed5, nh\u1eadn v\u1ec1 s\u1ed1 ti\u1ec1n 20.000 Vn\u0111. <\/li>
- C\u1eb7p s\u1ed1 ch\u01a1i l\u00e0 2: Tr\u00fang 1 trong 20 ho\u1eb7c kh\u00f4ng tr\u00f9ng con \u0111\u00e3 x\u1ed5 n\u00e0o xem nh\u01b0 thua. Ch\u1ec9 khi tr\u00fang c\u1ea3 hai m\u1edbi nh\u1eadn \u0111\u01b0\u1ee3c 90.000 Vn\u0111. <\/li>
- C\u1eb7p s\u1ed1 ch\u01a1i l\u00e0 3: Tr\u00f9ng 2 con nh\u1eadn 20.000 Vn\u0111, 3 con nh\u1eadn 200.000 Vn\u0111. Thua khi tr\u00f9ng d\u01b0\u1edbi 1 con. <\/li>
- C\u1eb7p s\u1ed1 ch\u01a1i l\u00e0 4: Tr\u00fang t\u1ed1i thi\u1ec3u ba con v\u1edbi m\u1ee9c \u0103n l\u1ea7n l\u01b0\u1ee3t 10.000, 50.000, 400.000. <\/li>
- C\u1eb7p s\u1ed1 ch\u01a1i l\u00e0 5: Tr\u00f9ng 4 s\u1ed1 150.000 Vn\u0111, ba s\u1ed1 nh\u1eadn 10.000 Vn\u0111, 5 s\u1ed1 4.400.000 Vn\u0111. <\/li>
- C\u1eb7p s\u1ed1 ch\u01a1i l\u00e0 6: Tr\u00f9ng 3, 4, 5, 6 nh\u1eadn ti\u1ec1n l\u1ea7n l\u01b0\u1ee3t 10.000, 40.000, 450.000, 12.500.000. <\/li>
- C\u1eb7p s\u1ed1 ch\u01a1i l\u00e0 7: Tr\u00f9ng 3, 4, 5, 6, 7 nh\u1eadn ti\u1ec1n l\u1ea7n l\u01b0\u1ee3t 10.000, 20.000, 100.000, 1.200.000, 40.000.000. <\/li>
- C\u1eb7p s\u1ed1 ch\u01a1i l\u00e0 8: Tr\u00f9ng 4, 5, 6, 7, 8 nh\u1eadn ti\u1ec1n l\u1ea7n l\u01b0\u1ee3t 10.000, 50.000, 500.000, 5.000.000, 200.000.000. <\/li>
- C\u1eb7p s\u1ed1 ch\u01a1i l\u00e0 9: Tr\u00f9ng 4 – 9 nh\u1eadn ti\u1ec1n l\u1ea7n l\u01b0\u1ee3t 10.000 – 800.000.000. <\/li>
- C\u1eb7p s\u1ed1 ch\u01a1i l\u00e0 10: Tr\u00f9ng 5 – 10 c\u1eb7p, nh\u1eadn ti\u1ec1n l\u1ea7n l\u01b0\u1ee3t 20.000 – 2.000.000.000. <\/li><\/ul>\n\n\n\n